an alkene was prepared by the dehydration of pentan-1-ol using concentrated sulphuric acid.?
Friday, August 21st, 2009 at
1:11 AM
the alkene produced?
is it pent-1-ene
1) Name and give structural formula of the product of the reaction of the alkene with:-
a) alkaline potassium permanganate
b) hydrogen bromide
c) chlorine
The thing is that i dont really understand what the answer is suppose to be.
and so need help
is it that when pentene reacts with a),b) and c) separately i have to name the compounds produced.
thanks for your help eveyone.
i owe u one.
Filed under: Potassium and Being Sick
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Yes, each reaction will take place with the C=C bond separately. You consider what would happen to each alkene + reagent.
a) Syn addition of a diol to the alkene to make
cis-pentane-1,2-diol
b) Markovnikov addition of HBr to the alkene to give
2-bromopentane
c) Anti-addition of Cl2 to the alkene to give
trans-1,2-dichloropentane
1) 1-pentene
2) If cold you get 1,2 pentane diol; if hot you get butanoic acid+ CO2
3) If reacted in the dark you get 2-bromopentane; if reacted in light or presence of ANY peroxides you get 1-bromopentane
4) If reacted with a little chlorine you’ll get 1,2 dichloropentane; if there is an excess of chlorine you’ll get an enormous array of di, tri, tetra…multiple chlorinated pentanes.
FYI you can’t get cis- or trans of an alkane (the mechanisms they give are correct but there is no double bond left to make anything have a cis- or trans conformation).