Chem Question 10 points will be given to best answer?
Saturday, February 27th, 2010 at
8:01 PM
Each 200mL of an electrolyte soultion designed for treating dehydration contains 0.47 g of sodium chloride (NaCl), 0.30 g of potassium chloride (KCl) and 3.56 g of glucose (C6H12O6).
a) Calculate the concentration of each compound in g L-1
b) Calculate the molarity of each compound
c) Calculate the concentration of potassium ions in the solution, in mol L-1
d) Calculate the concentration of chloride ions in the solution, in mol L-1
If you choose to answer this Question can you please show all your working out so i can learn from it. 10 points will be given to the best answer. thanks
Filed under: Potassium and Being Sick
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You have the mass of each compound in 200ml solution. Surely the mass in 1 litre of solution (= 1000ml ) must be 5 times each mass:
NaCl = 0.47*5 = 2.35g
KCl= 0.30*5 = 1.5g
C6H12O6 = 3.56*5 = 17.8g
Now that you have the mass per litre of solution, it is easy to work out the molarity
Molar mass NaCl = 23+35.5 = 58.5g/mol
2.35g = 2.35/58.5= 0.040mol dissolved in 1 litre solution: So
Molarity NaCl = 0.040M
Molar mass KCl = 39 +35.5 = 74.5g/mol
1.5g KCl = 1.5/74.5 = 0.020 mol in 1 lutre solution: So
Molarity of KCl = 0.020
Molar mass C6H12O6 = 6*12+12*1+16*6 = 180g/mol
17.8g C6H12O6 = 17.8/180 = 0.099 I am sure your teacher will accept:
Molarity of C6H12O6 solution = 0.1M
Concentration of K+ ions: You have calculated that KCl solution is 0.02M
KCl contains 1 atom K, So
Molar concentration of K+ ions = 0.02M
You have a contribution of Cl- ions from NaCl (0.04M ) and the KCl, (0.02M) so the total concentration of Cl - ions = 0.06
Molarity of Cl- ions = 0.06M
people on here cant even calculate 2+2