What volume of potassium hydroxide will result from the reaction of .170g of potassium with 100mL of water?
Wednesday, July 14th, 2010 at
5:36 AM
Please help with me with this problem by showing me the steps. I will reward the maximum amount of points for the answer showing the steps and the correct answer. Thank you!
Filed under: Water
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It is not feasible to calculate the volume of KOH formed. What is possible is to calculate the mol of KOH or the mass of KOH formed
Equation:
2K + 2H2O ? 2KOH + H2
1mol K will produce 1mol KOH
Molar mass K = 39.1g/mol
0.170g = 0.170/39.1 = 4.348*10^-3 mol K
Therefore you will produce 4.348*10^-3 mol KOH
Molar mass KOH = 56.1g/mol
4.348*10^-3 mol KOH = 4.348*10^-3*56.1 = 0.244g KOH produced
PS I did not worry about limiting reactants, because 100g H2O is in excess of 5mol H2O, so K is limiting.